2024 In fig. 6.2 bac 90° and ad  bc. then

In fig. 6.2 bac 90° and ad  bc. then

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WebMar 29, 2024 · Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved Next: Ex 6.2, 5 Important → Ask a doubt Chapter 6 Class 10 Triangles Serial order wise Ex 6.2 WebExample 5 : Observe Fig. 6.30 and then find P. Fig. 6.30 Solution : In ABC and PQR, Rationalised 2024-24 92 MATHEMATICS. AB 3.8 1 , BC 6 1 CA 3 3 1 and RQ 7.6 2 QP 12 2 PR 6 3 2. AB BC CA That is, RQ QP PR

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WebByju's Answer Standard X Mathematics Criteria for Similarity of Triangles In the given ... Question In the given figure, if ∠ADE= ∠B, show that ΔADE ∼ΔABC. If AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE. Solution In ΔADE and ΔABC, ∠A= ∠A (Common angle) ∠ADE= ∠B (Given) So by AA similarity, triangles are similar. So, by CPCT, WebApr 11, 2024 · In the given figure, if ∠BAC = 90° and AD⏊BC. Then, (A) BD.CD = AD2 (B) AB.AC = AD2 (C) BD.CD = AD2 (D) AB.AC = AD2 Ans: The correct option is (C): BD·CD = AD2 In ΔADB and ΔADC, It is given that ∠BDA = ∠ADC = 90° ∠B = ∠DAC = (90°- C) Now, by AA similarity criterion $\triangle \mathrm {ADB} \sim \triangle \mathrm {CDA}$ hof ptt

A quadrilateral ABCD is drawn to circumscribe a circle. Prove

WebAug 15, 2024 · Choose the correct answer from the given four options:1.In Fig. 6.2, Z BAC = 90° and ADI BC. Then,ABDCFig. 6.2… Get the answers you need, now! panditdineshchandras panditdineshchandras 16.08.2024 Math Secondary School answered Choose the correct answer from the given four options: 1. WebMar 22, 2024 · Ex 6.2, 1 In figure (i) ,DE BC. Find EC in (i) It is given that DE II BC Hence , / = / Putting the values 1.5/3 = 1/ 1.5 EC = 1 3 EC = (1 3)/1.5 EC = 2 cm Ex 6.2, 1 In figure (ii), … WebJun 3, 2024 · In Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° asked Aug 16, 2024 in Mathematics by AbhinavMehra ( 22.6k points) triangles hof puckhaber holste

In the given figure, if ∠ ADE = ∠ B, show that Δ ADE ∼Δ ABC. If AD …

Important Questions for Class 10 Maths Chapter 6 Triangles

WebGiven, ABC is an equilateral triangle with AD as altitude. We have to find the value of 4AD². We know that in an equilateral triangle all the sides are of equal length. Let AB = BC = AC = x units ----- (1) Let AD = h units ----- (2) In an equilateral triangle, the altitude AD bisects BC. So, BD = CD = BC/2 = x/2 WebOct 19, 2024 · Then Undefined control sequence \operatorname is equal to (а) 5 (b) 25 (c) (d) Answer 10. In ∠BAC = 90° and AD ⊥ BC. A Then (а) BD.CD = BC² (б) AB.AC = BC² (c) BD.CD = AD² (d) AB.AC = AD² Answer 11. D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE BC. huawei display 23.8 monitor 75WebClick here👆to get an answer to your question ️ In fig if ADE = ABC ,then show that ADE∼ ABC and AD = 6.8 cm, AE = 8.6 cm, BE = 2.4 cm and BC = 5.5 cm Find DE huawei display configuration

"WebIn figure, ∠BAC=90 o and AD⊥BC. Then A BD.CD=BC 2 B AB.AC=BC 2 C BD.CD=AD 2 D AB.AC=AD 2 Easy Solution Verified by Toppr Correct option is C) Given, In ABC, ∠A=90 … " - In fig. 6.2 bac 90° and ad  bc. then

In fig. 6.2 bac 90° and ad  bc. then

WebAug 5, 2024 · In the given figure, ∠A = 90°, AD ⊥ BC. If BD = 2 cm and CD = 8 cm, find AD. (2012; 2024D) Solution: ∆ADB ~ ∆CDA … [If a perpendicular is drawn from the vertex of the right angle of a rt. ∆ to the hypotenuse then As on both sides of the ⊥ are similar to the whole D and to each other ∴ … [∵ Sides are proportional AD 2 = BD , DC WebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given …

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WebJun 29, 2024 · In the given figure, ∠BAC = 90° and AD⊥BC. Then, (a) BC.CD = BC2 (b) AB.AC = BC2 (c) BD.CD = AD2 (d) AB.AC = AD2 triangles class-10 1 Answer +1 vote answered … WebIn the given figure, `angle BAC=90^(@) and AD bot BC`.then,

WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2. WebWe observe that ADB is a right angle triangle with D equal to 90 degrees. By Pythagorean theorem, AD² + BD² = AB² (h)² + (x/2)² = (x)². h² + x²/4 = x². h² = x² - x²/4. h² = [(4-1)/4]x². h² …

WebMar 16, 2024 · Ex 6.6, 4 In Fig. 6.59, ABC is a triangle in which ABC < 90 and AD BC. Prove that AC2 = AB2 + BC2 2 BC . BD.

WebIn Fig. 6.2, ∠BAC = 90° and AD BC. Then, a. BD . CD = BC 2 b. AB . AC = BC 2 c. BD . CD = AD 2 d. AB . AC = AD 2. Solution: Given, ∠BAC = 90° Also, AD BC. We know that a …

WebAug 1, 2024 · Solution: The figure is attached below In Triangle ABC, angle BAC = 90 degree and AD is perpendicular to BC Given in the question a perpendicular is drawn AD on BC from angle BAC which is 90 degree So, these two triangles ABD and CAD are similar By Corresponding part of Similar Triangles (CPST), hof puckhaberWebMar 29, 2024 · Transcript. Question 3 In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, BD . CD = BC2 (B) AB . AC = BC2 (C) BD . CD = AD2 (D) AB . AC = AD2 From Theorem 6.7, If a … Transcript. Question 4 The lengths of the diagonals of a rhombus are 16 cm and … huawei display power supplyWebMar 29, 2024 · Example 10 In figure, ∠ ACB = 90° and CD ⊥ AB. Prove that BC2/AC2=BD/AD Given:- ΔCAB, ∠ ACB = 90° And CD ⊥ AB To Prove :- BC2/AC2=BD/AD Proof : From theorem 6.7, If a perpendicular is drawn from the vertex of the right angle to the hypotenuse then triangles on both sides of the Perpendicular are similar to the whole triangle and to ... huawei discount offerWebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to … huawei display interface configurationWebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² … hof q bogenWebSolution Verified by Toppr Given:- Let ABCD be the quadrilateral circumscribing the circle with centre O. The quadrilateral touches the circle at point P,Q,R and S. To prove:- … huawei distributor thailandWebHere, the corresponding two sides and the perimeters of two triangles are proportional, then third side of both triangles will also in proportion. Question 8: If in two right triangles, one of the acute angles of one triangle is equal to an acute angle of the other triangle. Can you say that two triangles will be similar? Why? Solution: True huawei display monitor